Need Help With this Physics Problem (Please)

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SUMMARY

The discussion focuses on a physics problem involving a supersonic jet traveling at Mach 3, which is three times the speed of sound, at an altitude of 20,000 meters. The speed of sound is given as 345 m/s. The key calculations involve determining the time it takes for the shockwave to reach the ground observer and the horizontal distance the jet travels during that time. The solution utilizes the formula v = d/t and the Pythagorean theorem to find the relationship between the jet's position and the observer's position when the shockwave is heard.

PREREQUISITES
  • Understanding of Mach numbers and supersonic speeds
  • Knowledge of the speed of sound in air (345 m/s)
  • Familiarity with basic kinematics (v = d/t)
  • Proficiency in the Pythagorean theorem for distance calculations
NEXT STEPS
  • Study the principles of the Doppler Effect in relation to sound waves
  • Explore advanced kinematics problems involving supersonic motion
  • Learn about shockwave formation and its implications in aerodynamics
  • Investigate real-world applications of supersonic travel and its effects on sound perception
USEFUL FOR

Students studying physics, educators teaching kinematics and wave phenomena, and anyone interested in the principles of supersonic travel and sound waves.

jpnnngtn
This is the problem, anyone who can help me, please respond.

A supersonic jet traveling at Mach 3 (means that the speed of the jet is three times faster than the speed of sound in air) at an altitude of 20,000 m is directly overhead at t(time) = 0. How long will it be before the ground observer encounters the shockwave? Where will the plane be when it is finally heard? (Assume that the speed of sound in air is uniform at 345 m/s)


This problem is listed under the Doppler Effect in my textbook
 
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Looks pretty easy to me. I BELIEVE that the shock wave itself moves at the speed of sound (if that's incorrect I'm sure there will be people happy to jump on me with both feet :smile:).

Since v= d/t, t= d/v: 20000 m/345 m/sec.= how many seconds?

In the time that the shockwave takes to move the 20000 feet down, the jet, at three times the speed, will have moved three times as far, 60000 feet, horizontally. To find the straight-line distance between the person who hears the shock wave and the jet, use the Pythagorean theorem.

(I don't see how "Doppler Effect" has anything to do with it.)
 
you're right. Thank you. You have been most helpful. I think I was just confused because the problem was listed under the group of "Doppler Effect" problems.
 

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