Solving Hexane Condensation Problem: Flow Rate & Recovery

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SUMMARY

The discussion focuses on solving the hexane condensation problem involving a gas stream with 18.0 mole % hexane and nitrogen. The key calculations required are the flow rate of the gas stream leaving the condenser and the percentage of hexane recovered as liquid. The liquid hexane condensate is recovered at a rate of 1.50 L/min, and the mole fraction of hexane in the gas stream exiting the condenser is 0.0500. Participants emphasized the importance of applying mass balance principles to determine the molar flow rates of both the gas and liquid streams.

PREREQUISITES
  • Understanding of gas-liquid separation processes
  • Familiarity with mass balance equations
  • Knowledge of mole fraction calculations
  • Basic principles of fluid dynamics
NEXT STEPS
  • Calculate the molar flow rate of the hexane condensate
  • Determine the total flow rate of the gas stream using the mole fraction
  • Analyze the efficiency of hexane recovery in the condensation process
  • Explore advanced gas-liquid separation techniques
USEFUL FOR

Chemical engineers, process engineers, and students studying separation processes will benefit from this discussion, particularly those focused on gas-liquid interactions and recovery efficiencies in industrial applications.

jimithing
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A gas stream contains 18.0 mole % hexane and the remainder nitrogen. The stream flows to a condenser, where its temperature is reduced and some of the hexane is liquefied. The hexane mole fraction in the gas stream leaving the condenser is .0500. Liquid hexane condensate is recovered at a rate of 1.50 L/min.

a) what is the flow rate of the gas stream leaving the condenser?
b) what percentage of the hexane entering the condenser is recovered as liquid?

yikes, no idea where to start. probably should calculate the molar flow rate of the condensate since the rates at which the hexane and nitrodgen enter the unit must equal the total rates at which they leave in the two exit streams - but how?
 
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jimithing said:
- but how?

One step at a time. The problem statement as posted is missing information. What's missing? Is the information available elsewhere in the text or course materials? You've already got the concept of mass balance --- "what goes in has to come out," or, "what comes out has to have gone in." And, you've picked an excellent place to take the first step in solving ---

jimithing said:
probably should calculate the molar flow rate of the condensate

--- now, does that help, lead to more specific questions, or is everything still clear as mud?
 
figured it out in class today, thanks
 

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