Solving the Mystery of Calculating 10ul and 0.25ml for Protocol Steps

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Discussion Overview

The discussion revolves around understanding the calculations involved in a laboratory protocol for preparing solutions, specifically focusing on the addition of proteinase K and SDS to achieve desired concentrations. The scope includes technical reasoning and mathematical calculations related to solution concentrations.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant questions the calculation of 10 µL of proteinase K needed to achieve a final concentration of 50 µg/mL, suggesting that the dilution formula may not apply due to unknown total volume after adding the enzyme.
  • Another participant proposes that the calculation for proteinase K is logical and implies that the overall concentration can be derived from the given amounts.
  • A different participant attempts to clarify the calculation for the SDS concentration, noting that the percentage represents weight per volume and suggesting a method for calculating the required volume of SDS.
  • Further clarification is provided regarding the interpretation of weight/volume percentages, indicating that it can be expressed in grams per 100 mL, which may simplify calculations.

Areas of Agreement / Disagreement

Participants express confusion and seek clarity on the calculations, indicating that there is no consensus on the methodology for determining the volumes of proteinase K and SDS. Multiple interpretations and approaches to the calculations are presented without resolution.

Contextual Notes

Participants note the potential lack of disclosed information in the protocol that could affect calculations. There are also unresolved aspects regarding the conversion of percentage concentrations into usable volumes for the protocol.

Who May Find This Useful

This discussion may be useful for individuals involved in laboratory protocols, particularly those working with solution concentrations in biochemistry or molecular biology contexts.

sobored
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here is a part of the protocol we did:

a)spin down the chloroplast solution and decant the supernatant. add 4ml water to the pellet.

b) add 10ul proteinase K ( concentration= 20mg/ml) to get a final concentration of 50ug/ml.

-> how do they get 10ul? which formula do they use? i don't think that they use the dilution formula (C1 XV1= C2 X V2) since we don't know the total volume of the solution. it can't be 4ml, because when we add proteinase K the volume of the solution will increase.


c) then add slowly 0.25ml 10% or 0.125ml 20% SDS to get a final concentration of 0.5% SDS.

-> again, how do they come to 0.25ml 10% or 0.125ml 20% SDS to get a final concentration of 0.5% SDS?


i am very stucked, please help!
 
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Hello

Please remember that some protocols do not reveal some data in order to maintain full usage. Your approach is a logical one, so I conclude that there is something not disclosed.

10 microliters of proteinase K with a concentration of 20 mg/mL makes 10 micrograms of enzyme solution. I am sure you are aware of this. If you calculate the overall concentration, you may find the same result.

With the same way, they probably calculated the overall concentration of SDS in the final solution and required that you provide the same.

Regards
chem_tr
 
thank, you so much for helping me out! but i am still very confused, so i hope you will keep helping me out.

i have found the answer for a)

X/10ul=20ug/ul
X= 200ug

200ug/4ml= 50ug/ml.

this is what they get.

but, i can't figure out the answer of b) since the unit is in percent.


i am so confused so i really hope for replies!
thank you so much again!
 
The formula for percentage is the same you used for calculating the correct concentration of proteinase K. An easier to see it, the % represent Weight per volume. So you had 10 g of SDS into 100 mL of water so 10%=[1g/10mL]
 
Just to add a clarification to iansmith's post: A weight/volume solution expressed as a percentage can also be read to have units of g/100ml. It means exactly the same thing. Using g/100 ml in your calculations makes it far easier to balance your units and make sure your math is correct.
 

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