Help with homework??

[phywhat]

Runner A, who runs with an average speed of 3.0 m/s, starts out at 3:00 P.M. Runner B, who runs with an average speed of 4.0 m/s, starts after A from the same place exactly 5 min later.
a.) At what time will runner B catch up with runner A?
b.) If the runners stop when B catches A, how far do they run?

[needhelpperson]

this should go in the homework section... as well... you should show some work first, otherwise ppl are not going to help you.

[jdstokes]

Runner A, who runs with an average speed of 3.0 m/s, starts out at 3:00 P.M. Runner B, who runs with an average speed of 4.0 m/s, starts after A from the same place exactly 5 min later.
a.) At what time will runner B catch up with runner A?
b.) If the runners stop when B catches A, how far do they run?
You know v_A = 3 and v_B = 4 Integrating with respect to time gives x_A = 3t + C_A and x_B = 4t + C_B. When t=0, x_A = 0 so x_A = 3t. When t=300, x_B = 0, so x_B = 4t - 1200. Runner B catches runner A when x_A=x_B. That should be all you need to know.