dylanpuw
Aug14-10, 05:42 AM
(a)Determine the row rank of the matrix,
1 1 1 1
1 1 2 5
2 2 0 -6
(b) What is the column rank of this matrix?
(c) What is the dimension of the solution space Mx=0
So this is my answer:
I have reduced my matrix into echelon form and i get
1 1 1 1
0 0 -1 -4
0 0 0 0
Therefore my row rank is 2 (the number of linearly independent rows)
Since by rank theorem, (row rank = column rank = determinental rank) the column rank is also 2.
And the dimension of the solution space is 2 (number of columns - rank)
Is this answer correct?
Thank you
Dylan
1 1 1 1
1 1 2 5
2 2 0 -6
(b) What is the column rank of this matrix?
(c) What is the dimension of the solution space Mx=0
So this is my answer:
I have reduced my matrix into echelon form and i get
1 1 1 1
0 0 -1 -4
0 0 0 0
Therefore my row rank is 2 (the number of linearly independent rows)
Since by rank theorem, (row rank = column rank = determinental rank) the column rank is also 2.
And the dimension of the solution space is 2 (number of columns - rank)
Is this answer correct?
Thank you
Dylan