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UrbanXrisis
Sep9-04, 09:13 PM
I just got a review sheet in math that contain questions that I dont know how to do from last year. ONe asks to solve for all values of theta of [0,2pi] in radians: 2sin^2(theta)+sin(theta)-1=0

any ideas?

Leong
Sep9-04, 09:25 PM
Use
sin\ 2\theta = 2\ sin\ \theta\ cos\ \theta
sin^2\ \theta + cos^2\ \theta = 1

UrbanXrisis
Sep9-04, 09:42 PM
that confuses me more. I have no clue what the question is even asking, I think I forgot all my math. Could you give a longer explanation?

recon
Sep9-04, 10:15 PM
Let sin\ \theta\ = x

Then your original equation now looks like 2x^2 + x - 1 = 0.

Solve the quadratic equation. Once you do that, the rest should be easy.

Pyrrhus
Sep9-04, 10:31 PM
that confuses me more. I have no clue what the question is even asking, I think I forgot all my math. Could you give a longer explanation?

The question is asking for which angles in a 0 to 2pi interval satisfy that equation.

-Cyclovenom

Leong
Sep10-04, 03:30 AM
forget about what i have said. use recon's suggestion and understand cyclovenom's point.