View Full Version : Theorems about average values
Petar Mali
Sep1-10, 07:35 AM
\oint_{\Delta S}\vec{E}\cdot \vec{dS}=const \int_{\Delta_V}\rho dV
\Delta S surface which surround domain \Delta V.
\vec{E}(\vec{r},t) - vector field
\rho(\vec{r},t) - scalar field
Now in the book which I read they say we use average value theorem
and get
\oint_{\Delta S}\vec{E}\cdot \vec{dS}=const \overline{\rho}\Delta V
Can you tell me something more about
\int_{\Delta_V}\rho dV=\overline{\rho}\Delta V
HallsofIvy
Sep1-10, 08:46 AM
Well, there really isn't much to be said. The integral of a constant over a region is just that constant times the measure (length, area, or volume) of the region. Essentially you defining the average of a function to be that constant which, when integrated over the region, gives the same value as the integral integrated over the region.
It is just an extension of the average of a finite set of numbers: if the set of numbers is \{x_1, x_2, \cdot\cdot\cdot, x_n\} then adding them gives x_1+ x_2+ \cdot\cdot\cdot+ x_n and their average, \overline{x} is the number such that \overline{x}+ \overline{x}+ \cdot\cdot\cdot+ \overline{x}= n\overline{x}= x_1+ x_2+ \cdot\cdot\cdot+ x_n[[/tex]. That is,
[itex]\overline{x}= \frac{x_1+ x_2+ \cdot\cdot\cdot+ x_n}{n}.
Petar Mali
Sep1-10, 10:57 AM
Thanks! Idea is clear to me. But I have a trouble to determine when can I do that!
For example when can I say
\int^a_0f(x)dx=\overline{f}a
?
From
\oint_{\Delta S}\vec{E}\cdot \vec{dS}=const \overline{\rho}\Delta V
\frac{1}{\Delta V} \oint_{\Delta S}\vec{E}\cdot \vec{dS}=const \overline{\rho}
lim_{\Delta V \rightarrow 0}\frac{1}{\Delta V} \oint_{\Delta S}\vec{E}\cdot \vec{dS}
=lim_{\Delta V \rightarrow 0}const \overline{\rho}
(div\vec{E})_M=(const \overline{\rho})_M
where M is some point in region which volume (measure) is \Delta V.
And if I use Gauss theorem I will get
div\vec{E}=const\rho
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