Kinematic question.

[Kalu]

I've been trying this question, but I doubt the first answer...

An airplane with speed 97.5m/s is climbing upward at an angle of 50.0degrees with respect to the horizontal. When the plane's altitude is 732m, the pilot releases a package.
(a) Calculate the distance along the ground, measured from a point directly beneath the point of release, to where package hits the ground.
(b) Relative to the ground, determine the angle of velocity vector of package
just before impact.

For (a): I started used this equation Y = (Vf^2- Vi^2)/2a; plugged in the given values (97.5)^2/(2*9.8) = 485m. Is this correct. How do I start Q(B)?

I appreciate the help.

[arildno]

Why should you be able to use that equation in a)?
You don't know the the final speed..
In addition, your answer is meaningless; you were asked to find the distance traveled along the ground (measured from...).
Your answer contains no such information.
To give you a few hints:
1. Determine the initial vertical component of the package's velocity.
2. Calculate the time it will take to reach ground level.
3. Use that time to determine the horizontal distance traveled.