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physics_197
Nov6-10, 12:36 PM
1. The problem statement, all variables and given/known data

Given the equation of the plane to be: P = 0 + a[1,1,1]^T + b[x1,x2,x3]^T

and the point Y = [y1, y2, y3]^T

Show: (F)^T(Y-F)=0, where F is the point on the plane closest to Y

2. Relevant equations



3. The attempt at a solution


Y = F + FY
Y - F = FY

Now if somehow by multiplying both sides by F^T
F^T(Y - F) = F^T(FY)
and if F^T(FY) = 0, then I would be set, but I dont think it does(or atleast I dont have any properties that say it does)

HallsofIvy
Nov6-10, 01:21 PM
The shortest line from the point to the plane is perpendicular to the plane. That is, if F is the point on the plane closest to Y then the vector Y- F is perpendicular the plane and so is perpendicular to any vector in the plane.

You don't seem to be using the fact that plane is given by P = 0 + a[1,1,1]^T + b[x1,x2,x3]^T which is surely important! One thing that tells us is that the origin is in the plane so the vector F, the vector from the origin to the point F, is itself in the plane.

physics_197
Nov6-10, 01:48 PM
Thanks, got it