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wrong_class
Dec3-10, 04:43 PM
What are e and V in exponent of the equation I = I0(eeV/kT - 1)? is it really one variable "eV", as in electron volts, or is e just 2.718... and V for volts?

marcusl
Dec3-10, 04:59 PM
Two; e is the charge on an electron, V is the potential.

phyzguy
Dec3-10, 04:59 PM
It's confusing. The first e is just the base of the natural logarithms (2.718...), but the e in the exponent is the charge on the electron. I prefer to write it as:
e^\frac{qV}{kT} to eliminate this confusion. Note that if you measure kT in electron volts (eV), then the electron charges cancel, and you can just use the voltage V directly. Note that at room temperature, kT is .026 eV, so you can write:
I = I_0 e^\frac{V}{.026}

wrong_class
Dec3-10, 05:04 PM
Thanks!