A Problem from Work, Kinetic Energy, and Power

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SUMMARY

The discussion focuses on evaluating the work done by two distinct force fields, F(x,y) = y(i-hat) - x(j-hat) and F(x,y) = y(i-hat) + x(j-hat), on a particle moving from the origin to the point (1,1) along various paths. The key takeaway is that the first force field produces varying work values depending on the path taken, while the second force field yields consistent work values across all paths. Participants clarified that the work equations should be expressed as one-dimensional integrals rather than multidimensional integrals, emphasizing the need to define a parameter for each path.

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Homework Statement



A force field in two dimensions is given by F(x,y) = y(i-hat)-x(j-hat). A second force field in two dimensions is given by F(x,y)=y(i-hat)+x(j-hat). Evaluate the work done by each force on a particle that moves from the origin to the point (x,y)=(1,1) along each of the following paths: (a) (0,0)->(1,0)->(1,1) along the axes; (b) (0,0)->(0,1)->(1,1) along the axes; (c) y=x; and (d) y= x^2. Note particularly that the first force yields values that are not all the same while the second force yields values that are the same.

Homework Equations



Relavent multidimensional integral equations: http://web.uconn.edu/~cdavid/mathrev2/node8.html

The Attempt at a Solution



I'm not exactly sure how to write the Work equations in terms of multidimensional integral equations. I think I understand the physics, but the notation is confusing me. I'm really just looking for an example of how the work equations should be written.
 
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welcome to pf!

hi fiddleninja! welcome to pf! :smile:

(btw, on this forum it's easier to use the bold icon and write eg yi - xj :wink:)
fiddleninja said:
I'm not exactly sure how to write the Work equations in terms of multidimensional integral equations.

these aren't multidimensional integrals …

look at your own link, and you'll see they are path integrals (one-dimensional integrals), which should be easy …

you need to define a parameter s for each path, and do an ordinary one-dimensional integral over ds …

what do you get? :smile:
 
Thanks, I got it.
 

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