Solving Orthogonal Trajectories of a Family of Curves

Click For Summary
SUMMARY

The discussion focuses on determining the orthogonal trajectories of the family of curves defined by the equation y = √(2ln|x| + C). The user initially derived the derivative incorrectly but received guidance on simplifying the process. The correct approach involves squaring the original equation to obtain y² = 2ln|x| + C, differentiating with respect to y, and then using the negative reciprocal of the derivative to find the orthogonal trajectories. The final expression for the derivative is y' = 1/(xy).

PREREQUISITES
  • Understanding of differential calculus, specifically derivatives and implicit differentiation.
  • Familiarity with logarithmic functions and their properties.
  • Knowledge of orthogonal trajectories in the context of differential equations.
  • Ability to manipulate algebraic expressions and solve differential equations.
NEXT STEPS
  • Learn about implicit differentiation techniques in calculus.
  • Study the concept of orthogonal trajectories in differential equations.
  • Explore logarithmic differentiation and its applications.
  • Practice solving differential equations using the method of separation of variables.
USEFUL FOR

Mathematics students, educators, and anyone interested in advanced calculus, particularly those studying differential equations and their applications in geometry.

Maxwell
Messages
511
Reaction score
0
Here is the problem:

Determine the orthogonal trajectories of the given family of curves.

[tex]y = \sqrt{2\ln{|x|}+C}[/tex]

This is what I've done so far:

[tex]y = (2\ln{|x|}+C)^\frac{-1}{2}[/tex]

[tex]y' = -1/2(2\ln{|x|+C)(2/x)[/tex]

Now I understand to find the orthogonal lines I need to divide -1 by whatever I get, the problem is, I can't simplify this derivative.

I've messed around with it a bit, and I have this:

[tex]-(2\ln{|x|}+C)/x[/tex]

How else can I simplify this?

Thanks.
 
Physics news on Phys.org
First, your derivative is incorrect. Your final result may be written as

[tex]y' = \frac {1}{xy}[/tex]

Does that help?
 
Last edited:
Maxwell said:
Here is the problem:

Determine the orthogonal trajectories of the given family of curves.

[tex]y = \sqrt{2\ln{|x|}+C}[/tex]

This is what I've done so far:

[tex]y = (2\ln{|x|}+C)^\frac{-1}{2}[/tex]

Why is the power negative?

There is an easier way. Just square the original equation, and differentiate with respect to y.

[tex]y^2=2\ln{|x|}+C[/tex]

[tex]2yy'=\frac{2}{x}[/tex].
...
express y', take the negative reciprocal and you get the differential equation for the trajectories. Solve, it is easy.

ehild
 

Similar threads

Replies
32
Views
3K
Replies
64
Views
7K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
3
Views
2K
Replies
2
Views
1K
Replies
42
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K