Statics problem

[LewisNL]

The question is stated below. I found out an answer but it doesn't seems to be correct to me. I made a few sketches to clear things up a bit, sorry for bad quality, too much compression.

The simple truss of Prob. 4/2 is modified as shown in the figure, in that the angle of the support surface at C can be varied from 0 (vertical) to 90◦ (horizontal).

(a) Plot the force in member BC as a function of ø over this range. Note any unusual conditions.
(b) For what value of ø, if any, is the force in member BC zero?
(c) If member BC is designed to fail at a load of 5 kN in either tension or compression, what is the allowable range for the angle ø?

http://img.photobucket.com/albums/v213/Towbitis/Industrieel%20Ontwerpen/Staticsproblem4_138sketch.gif

Answers:
(a)
Fa = 500N
Fcx = Fbx + Fcx = 0
Fcx = -1200N
Fcy = tan(ø) = Fcy / Fcx
Fcy = -tan(ø) * -1200
Fbx = (Fa / 1,25) * 3 = 1200N
Fa + Fby + Fcy = 0
Fby = 500 – 1200 * tan(ø)

So if we want to plot this, x would be x = a vector from 0 to 90. And y would be y = –1200 * tan(ø).

If I plot this it shows some kind of weird looking tangens-function. Is this normal or did I make a miscalculation somewhere?

The function has a lot of 0-points so question (b) seems a bit strange too.

Maybe someone can help to clear things for me up a bit?

Thanks in advance :)

[Soveraign]

As a sanity check, given your diagram, it is clear that when theta is zero, the force pushing at C should be only in the -x direction and with magnitude you calculated above. Now, at theta approaches 90 degrees, I would expect that the force normal to the support surface C is sitting on to approach infinity.

Specifically in the y direction (the direction relevent to parts b. and c. of your question) the force would be zero when theta is zero and approach infinity as theta approaches 90 degrees.

Your equation for Fcy seems to follow this idea (although I'm not sure what you had declared as + and - in the y direction). Drawing out the vectors for myself, I get the following:
F_{cy} = 500N \frac{3m}{1.25m} \tan(\theta)

...which I think agrees with what you have. So, to solve the questions parts b. and c. it seems to me you would want to solve for when F_{cy} is zero and 5 kN.

Since you mentioned that your plot of the function had a lot of zero points, I feel I should ask if your plotting program is calculating tangent in degrees or radians?