View Full Version : How to calculate the contraction of metric tensor g^ab g_ab
yicong2011
Mar3-11, 12:03 AM
I wish I could calculate the contraction:
gabgab
I wish someone could show me how to get n!
Unfortunately, I find it difficult, for I am not familiar with Tensor Algebra ...
My wrong way to calculate it:
gabgab= gabgba (since gab is symmetric)
= δaa
= 1
Why is it wrong?
Matterwave
Mar3-11, 12:11 AM
So, you just sum over a and b...so it's like g00g00+g01g01+g02g02+g03g03+g10g10+g11g11+...all 16 terms
yicong2011
Mar3-11, 12:32 AM
But why the following is wrong? I cannot figure it out...
gabgab= gabgba (since gab is symmetric)
= δaa
= 1
Anyone can help???
JustinLevy
Mar3-11, 12:50 AM
The problem is your last step.
In four spacetime dimensions
\delta^a{}_a = 4
because
\delta^a{}_a = \delta^0{}_0 + \delta^1{}_1 + \delta^2{}_2 + \delta^3{}_3 = 1 + 1 +1 +1 = 4
yicong2011
Mar3-11, 02:06 AM
The problem is your last step.
In four spacetime dimensions
\delta^a{}_a = 4
because
\delta^a{}_a = \delta^0{}_0 + \delta^1{}_1 + \delta^2{}_2 + \delta^3{}_3 = 1 + 1 +1 +1 = 4
Ahh...Ja... [tex]\delta^a{}_a is not the components... I need to expand it and sum over the components...
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