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PAR
Mar4-11, 04:05 PM
1. The problem statement, all variables and given/known data
Name the following (organic) molecule:
http://img827.imageshack.us/img827/1883/organicmolecule.png (http://img827.imageshack.us/i/organicmolecule.png/)

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2. Relevant equations



3. The attempt at a solution

Would this be 3-pentene? The root has to be "pent" because that's the longest carbon chain, right?

Slats18
Mar4-11, 06:47 PM
3-pentene would actually be 2-pentene, and it would look something like this (excluding H's)

C-C=C-C-C or C-C-C=C-C

I see what you were trying to get at, but when you say 3-pentene, you're saying there is a 5 carbon chain that is the longest (correct) AND that there is a double bond connecting the 3rd and 4th carbon atoms =)

Here's my hint: try starting off at the double bond, and work your way up. What do you get now?

PAR
Mar4-11, 07:03 PM
3-pentene would actually be 2-pentene, and it would look something like this (excluding H's)

C-C=C-C-C or C-C-C=C-C

I see what you were trying to get at, but when you say 3-pentene, you're saying there is a 5 carbon chain that is the longest (correct) AND that there is a double bond connecting the 3rd and 4th carbon atoms =)

Makes sense, so is it 2-ethyl-1-butene? Does the fact that it contains a double bond take priority over the longest carbon chain?

Slats18
Mar4-11, 07:12 PM
That's what I believe it to be =) Been over a year since I've done this, but I think it does for convience, as its just a C=C double bond. Different when it's a C=O double bond, as you could call it 3-pentanone. Either way, I think it's just easier to call it 2-ethyl-1-butene =)

Borek
Mar5-11, 03:00 AM
IUPAC name is 3-methylidenepentane.