Cirle quation

[Phyphy]

I had x^2+y^2=Ae^x, how can i find out the cirle pass (0,1) and perpendicular to that cirle ? :frown:

[HallsofIvy]

I had x^2+y^2=Ae^x, how can i find out the cirle pass (0,1) and perpendicular to that cirle ? :frown:

Perpendicular to what circle? x2+ y2= Aex is NOT a circle!

[Phyphy]

sorry, it is curve not circle ? But I foun answer, I do sqare root of y and find y' and let it be a tangent's coeficent, and put it in a of y=ax+b, i found equation of y. :smile: :smile: