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Hooke's Law
Mar12-11, 10:21 AM
1. The problem statement, all variables and given/known data

I1, = 786 kJ molG1 I5 = 16,091 kJ molG1
I2 = 1577 kJ molG1 I6 = 19,784 kJ molG1
I3 = 3232 kJ molG1 I7 = 23,766 kJ molG1
I4 = 4355 kJ molG1 I8 = 29,251 kJ molG1

Determine the energy required in kJ molG1 for the following process:
M(g)^+ ------> M^5+(g) + 4 e



3. The attempt at a solution

I saw the solution sheet and it says "E = 25,255 kJ/mol (Sum of I2, I3, I4 and I5) Use Hess’s Law"

But why is it I2 to I5 and I thought it should be (products - reactants)
which I thought is I6 - I2. Could someone explain to me?

Thanks

Borek
Mar12-11, 11:48 AM
Write reaction equation for each Ix.

Hooke's Law
Mar12-11, 12:12 PM
I1 =M(g) ---> M^+(g) +e
I2= M+(g) ----> M2+ + e
I3 =M2+ ----> M3+ + e
I4 = M3+ ----> M4+ +e
I5 = M4+ ----> M5+ + e
I6 =M5+ ----M6 + +e

What's next?

Hooke's Law
Mar13-11, 07:04 AM
Did I do them right?

Borek
Mar13-11, 10:22 AM
OK, now, which reactions have to be combined?

Hooke's Law
Mar13-11, 10:51 AM
I still dont understand. What I'm thinking is still I6 - I1...

Borek
Mar13-11, 10:57 AM
I1 is about starting with Mg(0) - do you have Mg(0) in the process?

Hooke's Law
Mar13-11, 11:06 AM
No, I1 wont be in the process.

Borek
Mar13-11, 11:18 AM
What if I tell you that I6 is NOT Mg(0) -> Mg6+?

Hooke's Law
Mar13-11, 11:29 AM
Oh in my other previous post it should I6-I2. For I6 isnt it I6 =M5+ ----M6 + +e?

Borek
Mar13-11, 02:54 PM
Yes, I6 is Mg5+ -> Mg6+.

What reactions are needed to go from Mg(0) to Mg2+? Is I1 enough, or do you need I1 AND I2?

Hooke's Law
Mar13-11, 03:51 PM
I'm thinking I1 and I2 is needed.

Borek
Mar13-11, 04:55 PM
Yes, you need both. Now, which ones do you need to go from Mg+ to Mg5+?