Calculating New Blood Pressure with Drug-Induced Arteriole Radius Increase

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SUMMARY

The discussion focuses on calculating the new blood pressure after a 6% increase in the radius of arterioles due to drug administration. The original blood pressure is 160/100 mmHg. The new blood pressure is calculated using the formula for pressure change, resulting in new values of 160/(1.06)^2 and 100/(1.06)^2, which accounts for the increase in cross-sectional area of the arterioles. The calculations assume no change in heart output or stroke volume, confirming that increased radius leads to decreased pressure.

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  • Knowledge of cardiovascular physiology, specifically blood pressure dynamics.
  • Familiarity with the mathematical relationship between radius and area (r^2).
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HeatherMrkr
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please help asap!

:bugeye: I am not great at physics and am in an intro class for health sciences...here is my problem.
A person with a blood pressure of 160/100 takes a drug that causes a 6% increase in the radius of the arterioles. Find the new blood pressure assuming no change in heart output or stroke volume.
I tried 160/.06 and 100/.06 don't I have to do something with r^4? If I do that, I still come up with the wrong answers.
thanks!
Heather
 
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Pressure is defined by the force per unit area. The force is the same since no change in heart output has been assumed. The area concerned here is the area of the asterioles and is proportional to r^2. Since the radius increases, the area increases too and hence the pressure drops. The new pressures will be 160/(1.06)^2 and 100/(1.06)^2.

I am not very sure whether I answer your question correctly. Sorry if I did it wrongly.


Kenneth
 
thanks

Thanks for your help Ken!
 

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