Solving for Block's Acc, Kinetic Friction, and Speed

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Homework Help Overview

The problem involves a 3.00 kg block sliding down a 30-degree incline, with the goal of determining its acceleration, the coefficient of kinetic friction, the frictional force, and its speed after sliding 2.00 m over a period of 1.50 seconds.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using Newton's second law and kinematic equations to find acceleration and friction. There are questions about the formulas and the underlying theory. Some participants express a need for clearer explanations of the concepts involved.

Discussion Status

Some guidance has been offered regarding the use of specific equations to approach the problem. However, there is a mix of understanding, with some participants seeking further clarification on the formulas and concepts presented.

Contextual Notes

Participants are navigating through the problem with varying levels of familiarity with the relevant physics concepts and equations. There is an indication of a need for more foundational understanding among some contributors.

Frosty_TAW
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a 3.00 kg block starts from rest @ the top of a 30-degree and slides 2.00 m down in 1.50s. Find (a) the acceleration of the block (b) the coefficient of kinetic friction between it and the incline, (c) the frictional force acting on the block, and (d) the speed of the block after it has slid 2.00 m
please help! :confused: :confused:
 
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from what limited knowledge i have of this... all you would do is solev the for a using Newtons second law and then plug that into a kinematic eqtn (x = at^2/2) to find t and and then use Newtons second law again in another direction to solve for friction (mu)...

please tell me if you want a more quantitative result as i only listed th idea behind it...
 
what was that formula again i just need a better theory behind itm that was a little fast
 
for (a) use s=ut+0.5a(t2) where u=0 and s=2.0m and t=time to find a=acceleration


for (b) use
(mg sin#)-(u mg cos#)=ma

m=mass
a=acceleration from (a)
#=angle
g=9.8
u=coefficient


for (c) answer = u mg cos# :biggrin:

for (d) answer= u+at
u=0
a=accerletion
t=time


TADA!
OK!...now how abt a pay back @ pizza hut :devil:
 
thanks a million man, that really helps me out
 

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