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NightFire
Apr10-11, 03:52 PM
1. The problem statement, all variables and given/known data

Convert (AC3)16 to base 10.

I'm new to this kind of material. I would really appreciate your help for this one.
Thanks,
Roy


2. Relevant equations



3. The attempt at a solution
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution
tiny-tim
Apr10-11, 03:55 PM
Hi Roy! :smile:

Hint: what is (A00)16 to base 10 ? :wink:
eumyang
Apr10-11, 03:59 PM
See here (http://www.permadi.com/tutorial/numHexToDec/index.html) and try it yourself. Remember that:
the hexadecimal digit A corresponds to the decimal number 10,
the hexadecimal digit B corresponds to the decimal number 11,
...
the hexadecimal digit F corresponds to the decimal number 15.
NightFire
Apr10-11, 04:07 PM
so basically its: (10123)16 ?? did i convert it correctly?
eumyang
Apr10-11, 04:33 PM
No, it's not. Did you read the website that I linked in my previous post?
(here (http://www.permadi.com/tutorial/numHexToDec/index.html))
NightFire
Apr10-11, 04:38 PM
hi roy! :smile:

Hint: What is (a00)16 to base 10 ? :wink:

(1010100)10 ???
Zach Knight
Apr10-11, 06:59 PM
Consider the number 152 in base 10. Another way to write this number is 2*100+5*101+1*102.
If we change the base, we just change all of those tens. For example
152(base 8)=2*80+5*81+1*82=2+40+64=106(base 10)
Can you write AC3(base 16) in the form above?
NightFire
Apr10-11, 07:15 PM
Consider the number 152 in base 10. Another way to write this number is 2*100+5*101+1*102.
If we change the base, we just change all of those tens. For example
152(base 8)=2*80+5*81+1*82=2+40+64=106(base 10)
Can you write AC3(base 16) in the form above?

i see.
so basically i can write it this way?? : (AC3)16 = (10123)10
3*10^0 + 2*10^1 + 1*10^2 + 0*10^3 + 1*10^4 ????

Thanks
NightFire
Apr11-11, 02:35 PM
Somebody???! :(
SW VandeCarr
Apr11-11, 02:53 PM
i see.
so basically i can write it this way?? : (AC3)16 = (10123)10
3*10^0 + 2*10^1 + 1*10^2 + 0*10^3 + 1*10^4 ????

Thanks

In base 16, A=10 C=12 so 10(16^2) + 12(16) + 3 = 2560 + 192 + 3 = 2755 b10 = AC3 b16

What would FF be in base 10?
NightFire
Apr11-11, 03:31 PM
in base 16, a=10 c=12 so 10(16^2) + 12(16) + 3 = 2560 + 192 + 3 = 2755 b10 = ac3 b16

what would ff be in base 10?

10(10^2) + 12(10) + 3 = 1000+120+3= 1123

??
SW VandeCarr
Apr11-11, 04:11 PM
10(10^2) + 12(10) + 3 = 1000+120+3= 1123

??

You are wrongly multiplying on a base of 10. AC3 is a base 16 number so 16 is your base for conversion to base 10. 10 b16 = 16 b10; 100 b16= 16^2 = 256 b10; FF b16 = 255 b10. The base 16 "digits" are 0 1 2 3 4 5 6 7 8 9 A B C D E F. You are probably confused (as many are) because the same notation is used for the first ten digits (including zero). It would probably be better if we made up all new digits for different bases, but that's not the case. So 99 b16 = 9(16) + 9 = 144+9 = 153 b10. Nine (9) is not the highest digit in base 16.