Kinematic Equations

[Tom McCurdy]

Since a good amount of the posts refer to problems involving kinematics I figured this may be helpful

V_0 = Inital Velocity
V = Final Velocity
t= time
a= acceleration
x= distance

x=V_0t+\frac{1}{2}at^2

V=V_0+at

V^2=V_0^2+2ax

x= \frac{1}{2}(V_0+V)*t

[HallsofIvy]

Assuming that you mean "x is the distance traveled in time t" and that a is a constant, then
x= V_0t+ \frac{1}{2}t^2
NOT
x= V_0t*\frac{1}{2}t^2

[Tom McCurdy]

Very True... it does equal plus