Find radiation resistance of a wire

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SUMMARY

The discussion focuses on calculating the radiation resistance of a wire connected to a dipole antenna. The key equation used is P=I²R, where P represents power, I is current, and R is resistance. The average power is derived from the equation P=I²R, leading to the expression (qo²ω²R)/2, utilizing the average value of sin²(ωt) as 1/2. The participants clarify that the average power formula is Paverage = Irms²R = Imax²R/2.

PREREQUISITES
  • Understanding of dipole antennas and their configurations
  • Familiarity with electrical power equations, specifically P=I²R
  • Knowledge of sinusoidal functions and their average values
  • Basic concepts of alternating current (AC) analysis
NEXT STEPS
  • Study the derivation of radiation resistance in dipole antennas
  • Learn about the average power calculations in AC circuits
  • Explore the implications of sinusoidal waveforms in electrical engineering
  • Investigate the role of impedance in antenna design
USEFUL FOR

Electrical engineering students, antenna designers, and professionals involved in RF (radio frequency) engineering will benefit from this discussion.

leonne
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Find radiation resistance of a wire...

Homework Statement


Find radiation resistance of a wire joining the two ends of a dipole.

Homework Equations



P=I2R


The Attempt at a Solution


Ok so to solve this problem I need to set the average power = to total power and solve for R
I thought P=I2R is the average power, but its not and not sure how to find it.
The solution first finds P=I2R =qo2w2sin2(wt) R than somehow from this they get (qo2w2R)/2
No idea how they got that, no other formula in the section seems to fit this.
 
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hi leonne! :smile:

(have an omega: ω :wink:)
leonne said:
The solution first finds P=I2R =qo2w2sin2(wt) R than somehow from this they get (qo2w2R)/2

the average value of sin2ωt is 1/2 :wink:

(because sin2ωt = (1 + cos2ωt)/2)

the usual formula is Paverage = Irms2R = Imax2R/2
 


o ok thanks
 

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