What Was the Angle Between Two Objects in an Inelastic Collision?

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SUMMARY

The discussion centers on calculating the angle between two objects involved in a completely inelastic collision, where both objects have equal mass and initial speed v. After the collision, they move together at a speed of v/3. The solution utilizes the principle of momentum conservation, leading to the conclusion that the cosine of half the angle (θ) between their initial directions is given by the equation cos(θ/2) = 1/3.

PREREQUISITES
  • Understanding of momentum conservation principles
  • Familiarity with inelastic collisions
  • Basic trigonometry, specifically cosine functions
  • Knowledge of vector addition in physics
NEXT STEPS
  • Study the principles of momentum conservation in more complex collision scenarios
  • Explore the mathematical derivation of angles in inelastic collisions
  • Learn about different types of collisions, including elastic and perfectly inelastic
  • Investigate the application of trigonometric identities in physics problems
USEFUL FOR

Physics students, educators, and anyone interested in understanding collision dynamics and momentum conservation principles.

AERam
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This problem's got me stumped.

"After a completely inelastic collision between two objects of equal mass, each having initial speed v, the two move off together with speed v/3. What was the angle between their initial directions?"

Any help would be appreciated!
 
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Use momentum conservation. You should find that

[tex]\cos \frac {\theta}{2} = \frac {1}{3}[/tex]
 

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