A basic electrical question, but i can't work it out.

[MaximumTaco]

Say i have a DC battery, in parallel with a constant current source, and a resistor in parallel too.

I want to find the power dissipation in the resistor.

Do i consider that there are 2 current components superimposed, one from the voltage source
(I = v/r) and one from the current source, and then use I^2 *R?

Thanks.

[airbuzz]

if everything is in parallel, no matter what you put, the voltage in the parallel is given by the voltage of the dc battery so the current in the resistor is V/R.
In real word however, each battery has an internal resistor in series and a current generator has a resistor in parallel, so you should consider it.
In this case you can use the Millman´s Theorem, very easy.
Byez