PDA

View Full Version : Exponent laws


Nelo
Jul31-11, 05:05 PM
1. The problem statement, all variables and given/known data

2^-4 + 2^-6
_____________
2^-3


2. Relevant equations



3. The attempt at a solution

Ive tried several times, I do the reciprical of all numbers

ie) 1/2^4 + 1/2 ^6
___________________
2^3

Which gives me The wrong answer, cause i do the addiition first, finish all the powers and cant get the right answer. The book shows the next step to be...

2^2 + 1
________
2^6

Which i dont get

eumyang
Jul31-11, 05:08 PM
Don't rewrite the expression with positive exponents. (You did it wrong, anyway.) Instead, multiply the numerator and denominator by 26.

Nelo
Jul31-11, 05:16 PM
wat..? Dont make them positive yet multiply them with a positive denom. ? I dont even understand how the person got to 2^6.

eumyang
Jul31-11, 05:25 PM
It would also be helpful if you can check your original problem for typos. Because the problem you state:
\frac{2^{-4} + 2^{-6}}{2^{-3}}
does not equal the answer you state:
\frac{2^{2} + 1}{2^{6}}
wat..? Dont make them positive yet multiply them with a positive denom. ?
Sure, why not? If the original problem you stated was typed correctly, then I would multiply numerator by denominator by 26, because 2-6 is the smallest power of 2. 2-6 * 26 = 1, after all.

If you look at this similar example:
\frac{5^{-7} + 5^{-2}}{5^{-5}}
I would multiply top and bottom by 57 because 5-7 is the smallest power shown.