Work Energy problem

[Nothing]

A skier slides down a slope 10.2m long, inclined at an angle (theta) to the horizontal. The coefficient of kinetic friction is 0.11. Skier's initial speed is 1.9m/s and final speed at the bottom of the slope is 8.3m/s. Find (theta), air resistance is negligible.

I have applied F=ma and Work(friction) = (delta)Kinetic Energy + (delta) Potential Energy to it and found that these two r mathematically equivallent and terms just cancel when i substitue, can any1 help me with this one?

Thx

[ComputerGeek]

A skier slides down a slope 10.2m long, inclined at an angle (theta) to the horizontal. The coefficient of kinetic friction is 0.11. Skier's initial speed is 1.9m/s and final speed at the bottom of the slope is 8.3m/s. Find (theta), air resistance is negligible.

I have applied F=ma and Work(friction) = (delta)Kinetic Energy + (delta) Potential Energy to it and found that these two r mathematically equivallent and terms just cancel when i substitue, can any1 help me with this one?

Thx

try finding the height of the hill. you should then be able to solve for theta.

if you can find the Horizontal distance traveled, that would also be acceptable.

[Nothing]

How can i find the height with only one side of the triangle known? Where solving it would involve the angle itself?