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iggybaseball
Nov14-04, 07:47 PM
How would I change: 2x+3y=4
into polar form? I understand how to solve for polar form but the 4 without a variable is confusing me.

Phymath
Nov14-04, 07:54 PM
2 r cos \theta + 3 r sin \theta = 4
r(2 cos \theta + 3 sin \theta) = 4
2 cos \theta + 3 sin \theta = 4/r
\frac{4}{2 cos \theta + 3 sin \theta} = r

whats wrong with that?

iggybaseball
Nov14-04, 11:37 PM
Thank you I feel ashamed that such a simple problem stumped me. I was thinking to hard lol. Thanks again