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stonecoldgen
Sep8-11, 08:20 PM
1. The problem statement, all variables and given/known data
simplify:

(x^(a-1))/x^((3a+4))



2. Relevant equations

i was really dumb to think laws of logarithms would help me, but obviously not...

3. The attempt at a solution

the only thing i know is that the a's cant cancel!! i dont know what to do !!!

czelaya
Sep8-11, 08:27 PM
Think about the following:

x^a/x^b=(x^a)(x^-b)

Then,

(x^a)(x^-b)=x^[(a)(-b)]

In the problem you presented think FOIL.

eumyang
Sep8-11, 09:06 PM
1. The problem statement, all variables and given/known data
simplify:

(x^(a-1))/x^((3a+4))
Do you mean this?
\frac{x^{a-1}}{x^{3a+4}}
BTW, I don't mean to nitpick, but this is not an equation. It is an expression. Please don't confuse the two.

Think about the following:

x^a/x^b=(x^a)(x^-b)

Then,

(x^a)(x^-b)=x^[(a)(-b)]

In the problem you presented think FOIL.
If that's an a times negative b at the end, then that is not correct. We need to use one of the properties of exponents, mainly this one:
\frac{x^m}{x^n}=x^{m-n}