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vtnsx
Nov24-04, 09:56 PM
i've been trying to prove this question, but so far, there is no successs...
http://members.shaw.ca/brian103/theerrorfunction.jpg

Tide
Nov24-04, 11:39 PM
Does this help?

\int_a^b = \int_a^0+ \int_0^b

\frac {d}{dx} \int_0^x f(x') dx' = f(x)

ehild
Nov24-04, 11:40 PM
i've been trying to prove this question, but so far, there is no successs...
http://members.shaw.ca/brian103/theerrorfunction.jpg

a. Use the additive property of definite integral.

\int _0^bf(t)dt=\int_0^af(t)dt+\int_a^bf(t)dt

b. Remember that the differential quotient of definite integral with respect to the upper bound is the integrand itself.

\big[\int _0^xf(t)dt\big]' = f(x)


ehild