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physicsss
Nov27-04, 11:17 PM
I have no idea what the Q factor is in the following problem:

Consider a simple pendulum (point mass bob) 0.50 m long with a Q of 400.

How long does it take for the amplitude (assumed small) to decrease by two-thirds?

If the amplitude is 3.0 cm and the bob has mass 0.20 kg, what is the initial energy loss rate of the pendulum in watts? (The answer should have a negtive sign.)

If we are to stimultate resonance with a sinusoidal driving force, how close must the driving frequency be to the natural frequency of the pendulum?

Tide
Nov28-04, 12:33 AM
Q is the "quality factor" and is a measure of the energy loss per cycle:

Q = \omega \left| \frac {E}{\Delta E} \right|

Low Q means high damping and high Q means low dampiing. You should be able to take it from there!

physicsss
Nov29-04, 04:03 PM
How is the angular frequency related to amplitude and energy?

Tide
Nov30-04, 02:09 AM
The angular frequency is related to the length of the pendulum:

\omega = \sqrt \frac {g}{L}

and the amplitude will look something like

x = x_0 \cos \omega t

from which you can calculate the velocity and kinetic energy (and you can also obtain the potential energy).