Heaviside????? HELP

[slider527]

hey there peeps,

could u guys help me out with heaviside step function..cu zi don't understand anything bout how it works and how to apply to a particular problem...

could u guys explain in detail how to solve the next equations using heaviside:
exp[-2s]
F(s)= --------
s^2+s-2
and
__
|
| 0 for t<2
f(t) <
| t^2-2t+2 for t (greater or equal to ) 2
|__


ThnQ ...it means a lot to me :smile:

[fannemel]

The heaviside function is most easily explained as a on-switch.

h(u) = \left\{ \begin{array}{rcl}
\ 0 & \mbox{for} & t < u\right \\ 1 & \mbox{for} & t \geqq u
\end{array}\right

Thus if you multiply a function with the Heaviside function, the output are zero until the t = u, from that point, the function is similar to what it would look like without multiplying with Heaviside.

I didn't understand your notation so didn't get the equation, was it laplace?

[slider527]

The heaviside function is most easily explained as a on-switch.

h(u) = \left\{ \begin{array}{rcl}
\ 0 & \mbox{for} & t < u\right \\ 1 & \mbox{for} & t \geqq u
\end{array}\right

Thus if you multiply a function with the Heaviside function, the output are zero until the t = u, from that point, the function is similar to what it would look like without multiplying with Heaviside.

I didn't understand your notation so didn't get the equation, was it laplace?

well Laplace transformations are used to solve differential equations...
thnqs anyway,....mayb i can figure out woth u just said :confused:

[PerennialII]

could u guys explain in detail how to solve the next equations using heaviside:
exp[-2s]
F(s)= --------
s^2+s-2
and
__
|
| 0 for t<2
f(t) <
| t^2-2t+2 for t (greater or equal to ) 2
|__

I was kind of left somewhat puzzled what actually comes out of this notation ... could you clarify a bit ?