PDA

View Full Version : The zeroth component of the four-momentum


Identity
Nov12-11, 12:10 AM
Why is it that the Energy of a system is identified with p_0 and not p^0?

This is especially concerning to me in non-Minkowski metrics, such as the Schwarzschild metric, where the difference between p^0 and p_0 can be quite dramatic.

In the schwarzschild metric, we have:

p_0 = -\tilde{E}\,m

where \tilde{E} is energy per unit mass, and for a photon, p_0=-E

But that means that for a massive particle,

p^0 = m\left(1-\frac{2M}{r}\right)^{-1}\tilde{E}

and for a photon,

p^0 = \left(1-\frac{2M}{r}\right)^{-1}E

Clearly p_0 has been more closely related with energy than its contravariant form

atyy
Nov12-11, 12:43 AM
http://www.physicsforums.com/showpost.php?p=1908886&postcount=8

http://www.physicsforums.com/showpost.php?p=1910414&postcount=12

Identity
Nov12-11, 01:17 AM
thanks :)