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cycling4life
Nov16-11, 03:41 PM
I keep struggling to find a solution to this IVP. We are supposed to use integrating factors

y'-(1/t)y=8t^2+te^t
t>0, y(1)=6

I get an integrating factor of (1/t) and general solution of y=4t^3+te^t+c but then i get e+2 for c. This doesn't seem correct to me, any suggestions?

lurflurf
Nov16-11, 04:19 PM
That should be y=4t^3+te^t+c t