bwjohnson9
Dec5-04, 06:22 PM
Hello, I am having a problem solving part B of the following problem
A harmonic wave moving in the positive x direction has an amplitude of 3.8 cm, a speed of 36.0 cm/s, and a wavelength of 38.0 cm.
A) Calculate the displacement (in cm) due to the wave at x = 0.0 cm, t = 2.0 s. Assume that the displacement is zero at x = 0 and t = 0.
B) Calculate the displacement due to the wave at x = 10.0 cm, t = 20.0 s.
I got the answer to the first problem by using the equation
y=A x Sin (w x t)
f=velocity / wavelength = (.36m)/(.38m)= 0.94736
Period (T)= 1 / F = 1/0.94736 = 1.055
w= 2 x Pi/T = 2*pi / (1.055) = 5.9556
x= 2.3cm
This was fairly easy because x=0 and t=2 sec.
But I am not sure what to do when x= 10.cm and t= 20sec
Anybody got any tips?
A harmonic wave moving in the positive x direction has an amplitude of 3.8 cm, a speed of 36.0 cm/s, and a wavelength of 38.0 cm.
A) Calculate the displacement (in cm) due to the wave at x = 0.0 cm, t = 2.0 s. Assume that the displacement is zero at x = 0 and t = 0.
B) Calculate the displacement due to the wave at x = 10.0 cm, t = 20.0 s.
I got the answer to the first problem by using the equation
y=A x Sin (w x t)
f=velocity / wavelength = (.36m)/(.38m)= 0.94736
Period (T)= 1 / F = 1/0.94736 = 1.055
w= 2 x Pi/T = 2*pi / (1.055) = 5.9556
x= 2.3cm
This was fairly easy because x=0 and t=2 sec.
But I am not sure what to do when x= 10.cm and t= 20sec
Anybody got any tips?