Hypnos_16
Dec6-11, 01:41 PM
1. The problem statement, all variables and given/known data
10.11g of CaO (molar mass = 56.08 g / mol) is dropped into a styrofoam coffee cup containing 157.0 g of H2O at 25.0ºC. If the following reaction occurs, calculate the final temperature of the water assuming that the cup acts as a perfect insulator.
(Assume that the solution has the same specific heat capacity as water.)
CaO(s) + H2O(l) → Ca(OH)2(aq) ∆H = –64.8 kJ
m = 10.11 g of CaO + 157.0 g of H2O
∆T = (Tf - Ti) = (Tf - 25.0ºC
Cs = 4.184
q = -64800 J
2. Relevant equations
q = mCs∆T
3. The attempt at a solution
q = mCs∆T
-64800 = (167.11g)(4.184)(Tf - 25ºC)
-64800 = 699Tf - 17480
-64800 + 17480 = 699Tf
-47320 = 699 Tf
Tf = 67.7ºC
However i know that isn't right,
The answer i was given was to be 42.8ºC
So i'm confused as to what i did wrong...
10.11g of CaO (molar mass = 56.08 g / mol) is dropped into a styrofoam coffee cup containing 157.0 g of H2O at 25.0ºC. If the following reaction occurs, calculate the final temperature of the water assuming that the cup acts as a perfect insulator.
(Assume that the solution has the same specific heat capacity as water.)
CaO(s) + H2O(l) → Ca(OH)2(aq) ∆H = –64.8 kJ
m = 10.11 g of CaO + 157.0 g of H2O
∆T = (Tf - Ti) = (Tf - 25.0ºC
Cs = 4.184
q = -64800 J
2. Relevant equations
q = mCs∆T
3. The attempt at a solution
q = mCs∆T
-64800 = (167.11g)(4.184)(Tf - 25ºC)
-64800 = 699Tf - 17480
-64800 + 17480 = 699Tf
-47320 = 699 Tf
Tf = 67.7ºC
However i know that isn't right,
The answer i was given was to be 42.8ºC
So i'm confused as to what i did wrong...