Static friction force? mew? do what now?

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Homework Help Overview

The discussion revolves around understanding the concept of static and kinetic friction, specifically focusing on the coefficient of friction (referred to as "mew") in the context of a physics problem involving a crate being pushed with a certain force. The original poster expresses confusion about the problem setup and the role of the coefficient of friction.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the definition and implications of the coefficient of friction, question whether it pertains to static or kinetic friction, and explore the formulas related to frictional force and normal force. There is also an expression of frustration regarding the complexity of the formulas.

Discussion Status

Some participants have provided formulas and explanations regarding the relationship between frictional force and normal force, while others express confusion and uncertainty about the application of these concepts. There is no explicit consensus, but guidance has been offered to help clarify the problem.

Contextual Notes

The original poster mentions being absent and feeling confused about the problems, indicating a potential gap in foundational understanding. There is also a reference to the possibility of receiving a zero on the assignment, reflecting the pressure of homework expectations.

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:( static friction force? mew? do what now??

Okay, thanks for helping me first off.
Second, i was absent :( and now I'm pretty confused on a few problems that do with force.
the first of four problems, i don't understand, like, what exactly is mew?
ok ..
1. a 225 kg crate is pushed horizontally with a force of 710 N. If the coefficient of friction is .20, calculate the acceleration of the crate.
Heres what I've done:
225 kg= F sub g
710 N= F sub p
a = ?
now is the coefficient of friction static or kinetic? does it matter?
 
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Coefficient of friction is mew. Do you have the formula for coefficient of friction, the one with Ff in it? I can't recall the meaning of what coefficient of friction is but if you have your formula for it you should be able to find acceleration.
 
well, we have this formula..but its really confusing to me.
KINETIC FRICTION FORCE: Ff, kinetic=mewk times Force normal

? whoa that's got no acceleration. I am confused and frustrated :(
 
nevermind ill take a zero lol it doesn't matter.
 
I know how to do the problem now then. I'll give you some formulas and information, you can then try and attempt it.

Ff = Mew x Fn

Fn = -(Weight)
W = mg (gravity = g = -9.8 m/s^2
Weight is always negative. Fn (normal force) is what causes something to stay in place; therefore, it is opposite but equal to weight. Fn is positive.

Once you have Ff you know:

Fnet (net force) = Fapp (force applied) + Ff (force of friction)
Force of friction is negative:

Fnet= Fapp + (Ff) - The + will combine with the - from Ff and make the problem subtraction.

Once you have Fnet:

Fnet = ma
Rearrange

Fnet divided by mass = a

Then you have acceleration.
 
Yupp - that's right :)
 
To clear understanding...mew indeed is the coefficient of friction

it is defined as the Frictional Force (F of F) over (/) the Normal Force (F of N)

Mew helps to understand the tendency of an object to slide..

For instance, an object with .5 mew takes much more force to slide it horizontally than an object with a .3 mew.
 

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