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Does anyone know how to convert
cos^2 (2t)
into a form that I can use the Laplace-table on...?
How about using some trig identities:
\cos^2 2x = \frac {1 + \cos 4x}{2}
Hey thanks Tide! Just one thing, I wasn't really able to find this identity anywhere in my books, and I'm not really at a level where I can come up with such identities on my own if it goes beyond turning equations around. This identity is not one of the most used is it?
TSN,
It's just a variant of the sum formula which is very commonly used:
\cos a + b = \cos a \cos b - \sin a \sin b
so that when a = b
\cos 2a = \cos^2 a - \sin^2 a
and since
\sin^2 a + \cos^2 a = 1
the identity becomes
\cos 2a = 2 \cos^2 a - 1
from which
\cos^2 a = \frac {1 + \cos 2a}{2}
Finally, just set a = 2x for your problem.
Astronuc
Dec9-04, 08:44 PM
For trigonometric identities, try:
http://mathworld.wolfram.com/TrigonometricAdditionFormulas.html
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