Math Help:Reciprocal & Graphing

[Raza]

What would be the reciprocal of the following:

A)y=x^2

B)y=\sqrt{x}

I think the reciprocal for A, it would be:

y=\frac{1}{x^2}

And B would be:

y=\sqrt{\frac{1}{x}}

And also, How would I graph this?
I just need the table of values. Well, I need to do domain,range,graphing and a summary but I think I can do that myself if I get how to do the table of values.


Thanks :smile:

[Gokul43201]

If you are talking about reciprocals of numbers, then yes, the reciprocals of x^2~and~`\sqrt(x)~are~\frac{1}{x^2}~and~\frac{1}{\ sqrt(x)}

Since no domain has been provided in the question, you have to come up with what you think will be a relavant domain- ie : one which includes any "important" behavior.

For y = x^2 , I would pick a bunch of numbers say, from the set [-10, 10].

[futb0l]

oops - lol nvm.

[Raza]

Would this be the graph:
http://img.photobucket.com/albums/v384/cooolway/GraphReciprocal.jpg

The blue one is \frac{1}{x^2} and the red one is \sqrt{\frac{1}{x}}

[HallsofIvy]

One question: since if f(x)= x2 (for x>= 0), then f-1(x)= &sqrt;(x) are the functions you give, are you sure it is "reciprocal" that is intended rather than the inverse function?

[Raza]

I don't get your question. Please rephrase it.

[Nylex]

I don't get your question. Please rephrase it.

He means are you sure you're meant to be doing 1/y or should you be finding the inverse function (eg. the inverse of multiplication is division, the inverse of squaring is square rooting)?

[Raza]

I am sure that I don't have to find the inverse function.