Calculating Force from Parachute on Grade 11 Rocket Project

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Homework Help Overview

The discussion revolves around calculating the force exerted on a rocket by a parachute during its descent. The original poster describes their project involving a rocket and seeks assistance in determining the force from the parachute after it has ejected at maximum height.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the forces acting on the rocket and parachute system, including gravitational force and tension in the cords. There are questions about the role of air resistance and its equivalence to the force exerted by the parachute.

Discussion Status

Some participants have offered insights into the forces at play, referencing Newton's laws and the conditions for equilibrium. There is an acknowledgment of different interpretations regarding the forces involved, particularly concerning air resistance and its relationship to the parachute's force.

Contextual Notes

The original poster has provided specific values related to their rocket's mass and net acceleration, which may influence the calculations discussed. There is an indication of the poster's inexperience with physics terminology, which may affect their understanding of the concepts being discussed.

umer
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hi I've been doing rocets recently and i have to a report and analysis of my rocket

everything is going fine, i just got stuck on one question
i have to calculate the force exerted on the rocket from the parachute

so when the rocket reached its maximum, my parachute edjected...as it is coming down...wut is the force that the parachute is exerting on the rocket

ive thought aalot of about it but i just can't figure it out
i calculated my Acceleration Net to be around 15m/s

Fnet was around 1.27N
maximum height reached was 90.0m
mass of rocket was 66.01g <<<< this is without engine btw

i don't know if that helps :rolleyes:
i just need some direction/suggestion

thnx
 
Last edited:
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shouldnt the force be mg - because it should be in terminal velocity which is constant speed??
 
If you wait sufficiently long and the velocity of the descending rocket comes into equlibrium, according to Newton's Second and Third laws, there is no net acceleration of the parachute / rocket system. When that is the case all forces internal to the system must yield zero. The parachute pulls up on the cords that tie it to the rocket, while the cords pull the parachute down. Simultaneously (sp?) the cords pull up on the rocket while the rocket pulls down on the cords.

[tex]F_{p}-T=0[/tex]
[tex]T-mg=0 \therefore[/tex]
[tex]F_{p}-mg=0 \rightarrow F_{p}=mg[/tex]

I hope that helps.
 
Last edited:
Yupp - I agree with bobp718. Welcome to physicsforums btw ;)
 
what does Fp and T represent in that solution?

sry...im new to physics...its my year taking it so I am unfamiliar with these terms

thnx for the reply
 
[tex]F_{p}[/tex] was intended to be understood as the force that the parachute applied to the system.
[tex]T[/tex] was intended to be understood as the tension in the cord uniting the rocket and the parachute.
 
How about the air resistance?>
 
In this case, because of the function of the parachute, the air resistance would be the equivalent of the Force exerted by the parachute. So you do not need to calculate air resistance, once you find Fp you will already have it.
 
thank you soo much
it makes sense now
i really appreciate the help
 

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