Calculating net gravitational force on the moon

In summary, the net gravitational force on the moon can be determined using the equation Fnet = √(F1^2 + F2^2), where F1 and F2 are the forces exerted by the sun and earth respectively. Using the masses and distances provided, the correct value for the force between the sun and moon is 4.04x10^20 N and the force between the earth and moon is 1.97x10^20 N. The mistake in the calculation was using the incorrect value for the sun-moon distance. After correcting this, the net gravitational force on the moon is 4.49x10^20 N.
  • #1
rymath
2
0

Homework Statement



The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force vector F SM that the sun exerts on the moon is perpendicular to the force vector F EM that the Earth exerts on the moon. The masses are: mass of sun = 1.99 1030 kg, mass of Earth = 5.98 1024 kg, mass of moon = 7.35 1022 kg. The distances shown in the drawing are rSM = 1.5 1011 m and rEM = 3.85 108 m. Determine the magnitude of the net gravitational force on the moon.



Homework Equations


F=G m1m2/r^2
Fnet = √(F1^2 + F2^2)
G = 6.674x10^-11


The Attempt at a Solution


For the force between the Sun and the Moon I got 4.04x10^20 and for the force between the Earth and the Moon i got 1.97x10^20 N and then for the net force I got 4.49x10^20 N

I really don't know where I went wrong. I'm guessing my exponents are probably messed up? I've double and triple and quadruple checked it and I feel like my answer is right but WebAssign is saying I'm wrong. The calculations I used were

F(Sun and moon) = (6.674x10^-11(1.99x10^30 x 7.35x10^22)/(1.55x10^11)^2
Like I said, I got 4.04x10^20 N

F(Earth and moon) = (6.674x10^-11(5.94x10^24 x 7.35x10^22)/(3.85x10^8)^2
1.97x10^20 N

Fnet = √((4.04x10^20)^2 + (1.97x10^20)^2)

4.49x10^20 N

Thanks for any help!
 
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  • #2
rymath said:

Homework Statement



The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force vector F SM that the sun exerts on the moon is perpendicular to the force vector F EM that the Earth exerts on the moon. The masses are: mass of sun = 1.99 1030 kg, mass of Earth = 5.98 1024 kg, mass of moon = 7.35 1022 kg. The distances shown in the drawing are rSM = 1.5 1011 m and rEM = 3.85 108 m. Determine the magnitude of the net gravitational force on the moon.



Homework Equations


F=G m1m2/r^2
Fnet = √(F1^2 + F2^2)
G = 6.674x10^-11


The Attempt at a Solution


For the force between the Sun and the Moon I got 4.04x10^20 and for the force between the Earth and the Moon i got 1.97x10^20 N and then for the net force I got 4.49x10^20 N

I really don't know where I went wrong. I'm guessing my exponents are probably messed up? I've double and triple and quadruple checked it and I feel like my answer is right but WebAssign is saying I'm wrong. The calculations I used were

F(Sun and moon) = (6.674x10^-11(1.99x10^30 x 7.35x10^22)/(1.55x10^11)^2
Like I said, I got 4.04x10^20 N

F(Earth and moon) = (6.674x10^-11(5.94x10^24 x 7.35x10^22)/(3.85x10^8)^2
1.97x10^20 N

Fnet = √((4.04x10^20)^2 + (1.97x10^20)^2)

4.49x10^20 N

Thanks for any help!
Welcome to PF!

It looks like you used a slightly wrong value for the Sun-Moon distance in your calculation. Other than that, things look pretty good -- you are on the right track and your answer is not that far off.
 
  • #3
Redbelly98 said:
Welcome to PF!

It looks like you used a slightly wrong value for the Sun-Moon distance in your calculation. Other than that, things look pretty good -- you are on the right track and your answer is not that far off.

Thanks for pointing that out to me! I feel so dumb. Got the answer right!

Thank you so much :)
 

1. How is the net gravitational force on the moon calculated?

The net gravitational force on the moon is calculated by using Newton's Law of Universal Gravitation, which states that the force of gravity between two objects is directly proportional to their masses and inversely proportional to the square of the distance between them.

2. What is the formula for calculating the net gravitational force on the moon?

The formula for calculating the net gravitational force on the moon is F = G * (m1 * m2)/r^2, where F is the net gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects (in this case, the moon and the Earth), and r is the distance between them.

3. How is the distance between the moon and the Earth measured for calculating the net gravitational force?

The distance between the moon and the Earth is measured by using specialized instruments such as radar or laser ranging techniques, which can accurately determine the distance between the two objects.

4. Does the mass of the moon affect the net gravitational force on it?

Yes, the mass of the moon does affect the net gravitational force on it. According to Newton's Law of Universal Gravitation, the force of gravity is directly proportional to the masses of the two objects. Therefore, as the mass of the moon increases, the net gravitational force on it also increases.

5. How does the net gravitational force on the moon compare to that on the Earth?

The net gravitational force on the moon is significantly lower than that on the Earth. This is because the moon has a much smaller mass compared to the Earth, and the distance between the two objects is also much greater. As a result, the net gravitational force on the moon is only about 1/6th of the force on the Earth.

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