Rock is dropped off of a cliff physics homework

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SUMMARY

The physics problem involves calculating the height of a cliff from which a rock is dropped, with the sound of the splash heard 3.4 seconds later. The speed of sound is given as 340 m/s. The height can be determined using two equations: h = 1/2 g t12 and h = cs (3.4 s - t1), where g is the acceleration due to gravity (approximately 9.81 m/s2). By solving these equations simultaneously, the height of the cliff can be accurately calculated.

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DrZoidberg421
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I just started physics about a week ago. We got this problem for extra credit, and I need help with it.

A rock is dropped off of a cliff and the sound of splashing water is heard 3.4 seconds later. The speed of sound is 340 m/s. How high is the cliff?

Any insight/help you could give me would be great.

Thanks
 
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The height of the cliff is

[tex]h = \frac {1}{2} g t_1^2[/tex]

But h is also given by

[tex]h = c_s (3.4 s - t_1)[/tex]

where [itex]c_s[/itex] is the speed of sound. Can you take it from there?
 
Yeah, thanks a lot
 

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