Tension on each side of scaffold with window washer

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Homework Help Overview

The problem involves a scaffold supported by two cables, with a window washer positioned on it. The discussion centers around calculating the tension in each cable based on the weights involved and the positions of the individuals and objects on the scaffold.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculations of forces and tensions, with one original poster expressing uncertainty about which calculated tension corresponds to each cable. Others suggest clarifying the approach and being consistent with variable labeling.

Discussion Status

Some participants have provided guidance on using moments and free body diagrams to clarify the problem. There is an ongoing exploration of how to determine the correct tensions based on the window washer's position, but no consensus has been reached on the specific values assigned to each cable.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the depth of assistance provided. There is an emphasis on ensuring clarity in calculations and assumptions regarding the forces acting on the scaffold.

Kdawg
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A scaffold of mass 68 kg and length 6.1 m is supported in a horizontal position by one vertical cable at each end. A window washer of mass 77 kg stands at a point 1.7 m from one end.
What is the tension in the cable closer to the painter?
What is the tension in the cable further from the painter?
I calculated two forces 543.5 and 877.5, I am just not 100% sure what end each one is.
 
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Why don't you explain what you did. Its easier to determine if you are right that way.
 
I did it really quickly, and your answers seem right. In terms of determining which is which, be consistent with your variables and it should work out.
 
I first converted calculated the Force Weight because the answer needs to be in Newtons. Then I put a pivoit on the side closest to the window washer and balanced the forces.
(754.6 * 1.7) + (666.4 * 3.05) = 6.1x
543.5 = x
Then I subtracted that from the total downward force of 1421 to find the other side at 877.5
Im just not sure which side has what force.
 
No one knows this? I really need to do this soon.
 
Just take the moment at each end. Each one is only one equation one unknown.
 
Also, just looking at what side the window washer is on, you should intuitively determine which side will have more tension.
 
Label the force on the left side as T1 and the force on the right as T2. Then place the person somewhere on the bar. If you draw your free body diagram properly and are consistent with your variables you should be able to see which side is which.

You can also do it intuitively as Cantari suggested. Based on where the person is standing, which side do you think will have more tension?
 

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