Calculate Time Difference: Tim vs. Rick Running and Walking

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Homework Help Overview

The problem involves comparing the time taken by two individuals, Tim and Rick, to complete a journey of distance D, where they have different running and walking speeds. The context is rooted in kinematics, specifically focusing on time, distance, and speed relationships.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formulas for calculating the time taken by Tim and Rick, with some attempting to simplify the expressions for time difference. There is confusion regarding the correct approach to finding the difference in time, with participants questioning the algebraic simplification process.

Discussion Status

The discussion is ongoing, with participants offering different perspectives on how to approach the problem. Some have provided guidance on using specific formulas and rearranging equations, while others express uncertainty about their simplifications and calculations.

Contextual Notes

There is mention of a special case where the running and walking speeds are equal, which may influence the discussion. Participants are also grappling with the implications of subtracting Tim's time from Rick's time, indicating a potential misunderstanding of the time difference concept.

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Tim and Rick both can run at speed v_r and walk at speed v_w, with v_r greater than v_w. They set off together on a journey of distance D. Rick walks half of the distance and runs the other half. Tim walks half of the time and runs the other half.

the time it takes tim to cover the distance is:
t_R =((D/2)/v_w)+((D/2)/v_r)

the time it takes rick to cover the distance is:
t_T =2*D/(v_w+v_r)

In terms of given quantities, by what amount of time, Delta t, does Tim beat Rick?
It will help you check your answer if you simplify it algebraically and check the special case v_r = v_w.
Express the difference in time, Delta t in terms of v_r, v_w, and D.

this is an easy problem because all i need to do is take the Rick's time minus Tim's time right? I've done it and my answer is incorrect.
 
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You would take tim's time minus rick's time since tim takes less time. After that it is just algebra. All you have to do is simplify it.
 
Parth Dave said:
You would take tim's time minus rick's time since tim takes less time. After that it is just algebra. All you have to do is simplify it.


that's my problem. i couldn't simplify it correctly. i simplified it to be

(2D(VwVr)-D/2(Vr+Vw)(Vw+Vr))/((Vw+Vr)(VwVr))
but this is not the answer
 
A. use the formula d=v/t and rearrange it for time to t=d/v, since you have two v values (v_r and v_w), change the equation to t= (d/2vw)+(d/2vr). The two is in there because you multiple the distance by (1/2) which puts the two into the denominator.
B. The average speed is found by rearranging the answer to the above equation to answer for vw+vr, instead of time. You don't have to separate vw+vr when you get it on to the left side.
E. you DO have to subtract tims time from ricks because even though tim finishes first, rick takes LONGER thus a greater value for time. (or time would be negative otherwise)
 

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