Calculating Impulse of Golf Ball - Average Force of Impact

[UrbanXrisis]

A golf ball (m=46g) is struck a blow that makes an angle of 45 degrees with the horizontal. The ball lands 200 m away on a flat fairway. If the golf club and ball are in contact for 7 milliseconds, what is the average force of impact neglecting air resistance.

Here’s what I did.

$$d=\frac{v^2sin2\theta}{g}$$
$$200m=\frac{v^2sin90}{g}$$
$$1960=v^2$$
$$v=44.3m/s$$

$$I=mv-mv$$
$$I=0.046kg*44.3m/s$$
$$I=2.04Ns$$

$$I=Ft$$
$$2.04Ns =F(0.007s)$$
$$F=291.4N$$

Is this correct?

 

[Doc Al]

I didn't check your arithmetic, but your method is correct.

 

[Andrew Mason]

You ususally use a pitching wedge to get a 45 degree angle. 45 degrees - 200 m? That is some wedge shot.

AM