What Is an Example of a Nonintegrable Bounded Function?

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Homework Help Overview

The discussion revolves around identifying an example of a bounded function that is nonintegrable, specifically within the context of integration theory. Participants are exploring the characteristics of such functions and the implications of continuity and discontinuity on integrability.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants provide examples of functions, such as the Dirichlet function, and discuss the conditions under which functions are integrable. Questions arise regarding the definitions of integrability, particularly in relation to Riemann and Lebesgue integration.

Discussion Status

The discussion is active, with participants sharing examples and clarifying concepts related to integrability. There is an exploration of different types of integrability and the role of continuity in determining whether a function is integrable.

Contextual Notes

There is mention of the need for clarity on the definitions of Riemann and Lebesgue integrability, as well as the implications of discontinuity on integrability. Some participants note the importance of measure theory in this context.

matrix_204
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could someone give me an example of a function that is bounded but is nonintegrable?


i need to know what a nonintegrable function bounded on [a,b] is as said in my preperation file for a test? urgent help needed
 
Last edited:
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How about
[tex]f:(0,1)\rightarrow R[/tex],

[tex]f(x)=0,x\in ((0,1) \cap R-Q)[/tex]

[tex]f(x)=1,x\in ((0,1) \cap Q)[/tex]

Daniel.
 
yup thnx, i forgot we did an example of dirichilet function in class, this function is an example of a lot of things used in calculus, lol,
 
Always remember that continuity is a necessary condition for integrability...

Daniel.
 
Continuity is a sufficient condition for integrability, not a necessary one. A function that is discontinuous on a set of points of measure 0 is integrable, and vice versa (i.e. this gives a necessary and sufficient condition). Clearly, a continuous function is discontinuous on an empty set which of course has measure 0, so it is integrable. The example you gave is discontinuous on (0, 1), a set that doesn't have measure 0, which is why f is not integrable. Of course, this also depends on how you define integration and integrability.
 
Last edited:
Are u talking about Lebesgue,or Riemann integrability...?

Daniel.
 
dextercioby: The function f(x)= 0 if x< 0; 1 if 0< x< 1; 0 if x> 1 is (Riemann) integrable over any interval but is not continuous at 0 and 1.

The function: f(x)= 0 if x is rational; 1 if x is irrational is (Lebesque) integrable over any interval but is not continuous anywhere.
 
AKG's right, I'm pretty sure. IIRC, A bounded function is Riemann integrable over a compact set iff it's discontinuous on a set of measure zero.
 

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