Electron bound to proton by gravity

  • #1
Juli
21
5
Homework Statement
Suppose an electron were bound to a proton not by the electrical force, but by gravity. What would be the radius and energy of Bohr's first orbit?
Relevant Equations
##F_G = \frac{G\cdot m_1 m_2}{r^2}##
##F_C = m_e r \omega^2##
Hello everyone,
I have the problem above. I chose to put ##F_G = F_Z## to solve it and end up with a radius ##r = 1.04\cdot 10^{-7}##m.
Solutions on the internet choose to put the gravitational force equal to the centrifugal force and obviously end up with a completely different solution. I can kind of understand both ways, but for me my way is the solution to the above statement, and to put ##F_G## equal to the coulomb force would just show how big the radius has to be to equal the Coulomb force. Which of course is valid because this is how the electron is bound to the proton. But in the problem we think about, how it is, when the Coulomb force is not there.
Which way would you think is correct to solve what is asked?
 
Physics news on Phys.org
  • #2
Why do you think the gravitational force between the proton and electron has to equal the electrical force?

In a normal hydrogen atom, the sum  of the gravitational and electrical forces between the proton and electron provides the centripetal force on the electron. You can neglect the gravitational force as it is  much  weaker than the electric force.

But if there is no electric force, the centripetal force on the electron has to be provided entirely by the gravitational force.

Does that make sense?
 
  • #3
Hello, thank you for your answer. I was just about to delete this post, since I got the right solution by using my method. I was wondering anyway, that if the Coulomb force was set equal to the centrifugal force and the gravitational force was set equal to the centrifugal force, that the Coulomb and the gravitational force had to be equal. And that is what I got now. I think I made som e major mistakes in the way I calculated my first solutions.
 
  • #4
Juli said:
I was just about to delete this post, since I got the right solution by using my method.
What answers (radius and energy) did you get? Hopefully the radius was very (and I mean very!) large.

Juli said:
I was wondering anyway, that if the Coulomb force was set equal to the centrifugal force and the gravitational force was set equal to the centrifugal force, that the Coulomb and the gravitational force had to be equal. And that is what I got now. I think I made som e major mistakes in the way I calculated my first solutions.
You mean centripetal, not centrifugal.

You shouldn't set the Coulomb and gravitational forces equal here; it's wrong. The 1st Bohr orbit is determined by ensuring that the electron's angular momentum is the required value.
 

1. How does gravity affect an electron bound to a proton?

Gravity is a relatively weak force compared to the electromagnetic force that binds an electron to a proton in an atom. However, gravity does play a role in keeping the electron in orbit around the proton by providing the centripetal force necessary to maintain its circular motion.

2. Can gravity cause an electron to fall into the nucleus of an atom?

No, gravity alone is not strong enough to overcome the electromagnetic force that repels the negatively charged electron from the positively charged proton in the nucleus. The electron remains in orbit around the nucleus due to the balance of these two forces.

3. How does the mass of the electron and proton affect the gravitational attraction between them?

The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. The relatively small masses of the electron and proton result in a very weak gravitational attraction compared to the electromagnetic force that holds them together.

4. Is gravity the primary force that binds an electron to a proton in an atom?

No, the primary force that binds an electron to a proton in an atom is the electromagnetic force. This force is much stronger than gravity and is responsible for the structure and stability of atoms. Gravity plays a minor role in keeping the electron in orbit around the nucleus.

5. Can the gravitational force between an electron and a proton be measured experimentally?

Due to the extremely weak nature of the gravitational force between an electron and a proton, it is currently not possible to directly measure this force in a laboratory setting. The effects of gravity at the atomic scale are overshadowed by the much stronger electromagnetic interactions that govern atomic behavior.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
660
Replies
2
Views
943
  • Introductory Physics Homework Help
Replies
21
Views
669
Replies
11
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
769
  • Introductory Physics Homework Help
Replies
10
Views
453
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
754
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
1K
Back
Top