Seemingly easy electric potential problem

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Homework Help Overview

The discussion revolves around calculating the electric potential created by two point charges located on the x-axis, specifically at a point on the y-axis. The charges are both of equal magnitude, and participants are exploring the implications of their signs on the potential at the specified location.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the significance of the charges' signs and how they affect the electric potential, noting that potential is a scalar quantity. There is also discussion about the implications of the charges being positive or negative and how this affects the potential at the point on the y-axis.

Discussion Status

Some participants have provided clarifications regarding the nature of electric potential as a scalar, while others are still grappling with the implications of the problem's wording and the calculations involved. There appears to be a productive exchange of ideas, although no consensus has been reached on the final answer.

Contextual Notes

Participants are navigating the ambiguity in the problem's wording regarding the charges' signs and their implications for the potential along the y-axis. There is an emphasis on understanding the fundamental properties of electric potential in relation to point charges.

bemigh
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Hey everyone, check out this question:

Two point charges each of magnitude 2.14 µC are located on the x axis. One is at x=1.39 m, and the other is at x=-1.39 m. Determine the electric potential on the y-axis at y=0.505 m

Alright, so I am working on it, as you do, but then i realized, that the original point charges, the MAGNITUDE of the charges is given. This causes problems. Because then the direction of electric field at the point on the Y axis can have many different directions (when the charge of the original points change). For instance, if both charges are positive, the electric field at the point on the Y axis is 6007.36 N/C, however, if one of them is negative, the field is now 16535.14 N/C (when you add the sum of the vectors, etc etc...

Anyone have any insight??
Cheers
Brent
 
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Potential is a scalar quantity, not a vector. But of course it does matter whether the charges are positive or negative. The wording is a bit ambiguous, but I'd assume they mean both are positive. Otherwise, what could you say about the potential along the y axis?
 
Hey, Brent again,
I understand what you mean, the potential should be equal all along the Y axis, because along every point of the axis, it is equidistant to each charge. I stll can't seem to find the answer...
Cheers
 
This is worth repeating, 'cause you seem to be overlooking it:

Potential is a scalar quantity, not a vector.

What are you doing with vectors?
 

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