Graphing f(x)=2^2+9/5x^2+2: Imaginary #s

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Homework Help Overview

The discussion revolves around graphing the function f(x) = (2x^2 + 9) / (5x^2 + 2), with a focus on understanding its asymptotic behavior, particularly regarding imaginary numbers and vertical asymptotes.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the nature of the function's asymptotes, questioning the presence of vertical asymptotes and discussing the implications of imaginary numbers in graphing.

Discussion Status

Some participants have clarified the function's form and identified the horizontal asymptote, while others are questioning the relevance of imaginary numbers in the context of graphing real functions.

Contextual Notes

There appears to be confusion regarding the function's structure and the interpretation of asymptotes, particularly the distinction between real and imaginary values.

Rasine
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i need to graph f(x)=2^2+9/5x^2+2

the vertical asym. would be the i squareroot10/2 ?

if that is correct how do i graph an imaginary #
 
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You're telling me you need to graph

[tex]9/5x^2+6[/tex]

?
 
no in the numerator is: 2x^2+9
denomorator is: 5x^2+2
 
So it is

[tex]\frac{2x^2+9}{5x^2+2}[/tex]

and you have to sketch the graph?
 
It has horizontal asymptote at y=2/5 and no vertical asymptotes since the denominator is never zero.
 
thank you very much
 
Yes,asymptotes (especially vertical ones) refer to REAL values for numbers...

Daniel.
 

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