Calculating Angular Width of Central Maximum in Wave Diffraction

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SUMMARY

The discussion focuses on calculating the angular width of the central maximum in wave diffraction using a single gap. The wavelength of the waves is 2m, and the width of the barrier is 10m. The formula used for determining the angular separation from the central maximum to the first-order minimum is sin(theta) = (n * lambda) / d, where d is the gap width and n is the order of the minimum. In this case, n equals one, simplifying the calculation process.

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Waves with wavelength 2m pass through a hole in a barrier 10m wide. Compute the angular width of the central maximum.

I'm not sure what I am finding here. Is it the angel between the central maximum and the 1st nodal line?...If so am I treating this like a 2 point source problem?

Any help would be great!
 
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This is a "single gap" problem, but the formula is (sometimes) identical to the 2-slit problem. With a single gap, the angular separation from central maximum to the first-order minimum is given with the formula sin theta = (n lambda) / d .

Here d is the width of the gap and n is the "order" (one in this case).

With 2-slit interference, d is the separation of the slits, and theta gives you the angular position of the first order maximum.
 
ahh thanks...easier than I thought.
 

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