Help with 0.999...=1 Project - Urgent Assistance Needed

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The discussion centers on the mathematical proof that 0.999... equals 1, utilizing the concept of limits in sequences and series. The user presents a sequence where each term approaches 1, demonstrating that the distance from 0.999... to 1 converges to zero as the number of nines increases. The proof employs algebraic manipulation, defining x as 0.999... and showing that 10x equals 9 plus x, leading to the conclusion that x equals 1. This establishes that 0.999... is indeed equal to 1 by definition.

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chickenguy
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Need urgent help

:approve: sorrypeople if this annoys u but please don't close this thread. i need urhent help with my 0.999...=1 project and i have a new thing my teacher told me would help, but i don't understand!
0.9=1- 1/10(fraction)
0.99=1-1/100(fraction)
0.999=1- 1/1000(fraction)
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1-(approaches zero)=1

sequence and series.
______________________
Also, any background information and/or history and/or opinions and/or information would be very greatly appreciated!1 o:)
 
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OPinions are not required. The real numbers are by construction somewhere where convergent sequences of rationals have unique limits. the sequence 0.99..9 with n nines converges to 1, that is what the above states - the distance from it to 1 is 10^{-n} which converges to zero.

so 0.999... the infinite string of nines which, by definition also represents the limit of that sequence mustbe equal to one by fiat.
 
Let x = 0.999999...
10x = 9.999...=9+0.999...=9+x
10x - x = 9
9x = 9
x=1

0.999... = 1
 

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